Printing a Metrics in Diagonal Order ass 9

Problem Statement
Write a C program that reads the order N(≤ 20) of a square matrix over data of type

 double. Then it reads the matrix in row-major order in a 2-D array (type double).

 It prints the input data,

 It prints the matrix in diagonal order,

 It prints the matrix in anti-diagonal order, and

It prints the matrix in anti-clockwise spiral order

i.e when the metrics is 

   1 2 3

   4 5 6 

  7 8 9

then  Diagonal order:  7 4 8 1 5 9 2 6 3

Anti-Diagonal order:  1 2 4 3 5 7 6 8 9

Anticlockwise-Spiral order: (odd order matrix) 1, 4, 7, 8, 9, 6, 3, 2, 5

and so on

#include<stdio.h> int main() { int i,j,n,count; printf("enter the value of n \n"); scanf("%d",&n); double a[n][n]; printf("enter the values rowwise \n"); for(i=0;i<n;i++) { for(j=0;j<n;j++) { scanf("%lf",&a[i][j]); } } printf("\nyour value are are read as\n"); for(i=0;i<n;i++) { for(j=0;j<n;j++) { printf("%lf ",a[i][j]); } printf("\n"); } printf("\nnow i print the matrics in diagonal order \n"); i=n-1; j=0; while(i!=0||j!=(n-1)) { count=0; while(i<n&&j<n) { printf("%lf ",a[i][j]); i++; j++; count++; } if(j==count&&count==i) { i=0; j=1; } else if(j==count&&j!=i) { i=i-count-1; j=0; } else if(i==count&&i!=j) { j=j-count+1; i=0; } if(i==0&&j==(n-1)) { printf("%lf ",a[i][j]); } } return 0; }