sum of series 1+(1/2)+(1/3)...+(1/n)

Problem Statement
Write a c program to calculate the sum of the series
1+(1/2)+(1/3)...+(1/n)
you should take the value of n as an input from the user

#include<stdio.h>
int main()
{
  float sum,i,n;
  printf("enter the value of n:\n");
  scanf("%f",&n);
  sum=0.0;
  for(i=1.0;i<n+1;i++)
    {
      sum=sum+(1/i);
    }
  printf("the sum is equal to :%f",sum);
  return 0;
}